Asked by Anonymous
A 4.29 kg block starts from rest at the top of a 31.8 degrees incline and slides 2.22 m down the incline in 1.22 s. The acceleration of gravity is 9.8 m/s^2. What is the acceleration of the block? Answer in units of m/s^2
What is the coefficient of kinetic friction between the block and the incline?
What is the frictional force acting on the block?
Answer in units of N
What is the speed of the block after it slid the 2.22 m? Answer in units of m/s
What is the coefficient of kinetic friction between the block and the incline?
What is the frictional force acting on the block?
Answer in units of N
What is the speed of the block after it slid the 2.22 m? Answer in units of m/s
Answers
Answered by
PhysicsPro
<vx)-ln[.03]/(l1)<l3>
A shortcut I forgot about until calc III is to make it a function of <vx)
vx=nnx+bbn+c
c(x)=<l.5/.556>
nn(x)
x=nn(.565)
bbn
n=(bb)=.909
c=vvx/.909[pi]^2<nnx>
C=?
A shortcut I forgot about until calc III is to make it a function of <vx)
vx=nnx+bbn+c
c(x)=<l.5/.556>
nn(x)
x=nn(.565)
bbn
n=(bb)=.909
c=vvx/.909[pi]^2<nnx>
C=?
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