Asked by April
A 7.4kg block starts 1.2m above the ground, at the top of a frictionless ramp. At the bottom of the ramp is a flat stretch of rough (μk = 0.15) ground 3.0m long. After sliding 3.0m, the ground becomes frictionless, and the block hits a spring (k = 1.6kN/m).
a. Calculate the speed of the block at the bottom of the ramp.
a. Calculate the speed of the block at the bottom of the ramp.
Answers
Answered by
Scott
1/2 m v^2 = m g h
v = √(2 * 9.8 * 1.2)
v = √(2 * 9.8 * 1.2)