Question

13.98mL of 2.902M HCl are reacted with 15mL of 3.198M NaOH. Use the molar heat of neutralization to determine the kJ of heat produced.
What is the molar heat of neutralization?
the molar heat of neutralization is -55.84kJ/mol
moles NaOH = M x L(this is in excess)
moles HCl = M x L(limiting reagent)

moles HCl reacted x 55.84 kJ/mol = xx kJ heat released.

Related Questions

when 12.76mL of HCl of unknown concentration (but less than the base) are reacted with 15mL of 3.254... 3.98mL of 2.902M HCL are reacted with 15mL of 3.198 M NaOH. Use molar heat of neutralization to dete... A mixture of NaOH and HCl is formed in a calorimeter. There is 50 mL of 2.078 Molar HCl and 51.7mL o...