Question
If 35.0 mL of 0.210 M HCl reacts with excess Mg, how many mL of hydrogen gas are produced at STP?
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
Is the answer 2.352 STP
converted mols HCl to mols H2 gas:
02.10 M HCl x 1 mol H2/2 mol HCl = 0.105 mol H2
converted mols H2 gas to L:
0.105 mol H2 x 1L/1 mol= 0.105 L H2
multiplied L of H2 to 22.4 STP
0.105L x 22.4 STP= 2.352
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
Is the answer 2.352 STP
converted mols HCl to mols H2 gas:
02.10 M HCl x 1 mol H2/2 mol HCl = 0.105 mol H2
converted mols H2 gas to L:
0.105 mol H2 x 1L/1 mol= 0.105 L H2
multiplied L of H2 to 22.4 STP
0.105L x 22.4 STP= 2.352
Answers
DrBob222
No. You don't have 2.10 mols HCl. Did you read my response? mols HCl = M x L = 2.10 x 0.035 = ?
Then convert to mols H2 and from thre to L.
Then convert to mols H2 and from thre to L.