Asked by Anonymous
3.98mL of 2.902M HCL are reacted with 15mL of 3.198 M NaOH. Use molar heat of neutralization to determine the kJ of heat produced. molar heat of neutralization is -55.84kJ/mol.
Answers
Answered by
DrBob222
55.8 kJ/mol x # moles = ?? kJ.
# moles = (3.98 mL/1000) x 2.902 M = ??
# moles = (3.98 mL/1000) x 2.902 M = ??
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