Asked by gen
differnetitae the function:
y= 2x^-1/2 + 4x^-3/2
y= 2x^-1/2 + 4x^-3/2
Answers
Answered by
Reiny
just use the chain rule on each term
dy/dx = - x^(-3/2) - 6x^(-5/2)
(convention:
since the original was written with negative rational exponents, the resulting derivative can also be left in that form)
dy/dx = - x^(-3/2) - 6x^(-5/2)
(convention:
since the original was written with negative rational exponents, the resulting derivative can also be left in that form)
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