Asked by Ann
For the function
f(x)=3x^3−42x
Compute the difference quotient
[f(x+h)−f(x)]/h,h≠0
I checked my work like 3 times and still got [(-2x^3)+(3hx^2)+(3xh^2)+(h^3)-(42h)]/h
Is it wrong?
f(x)=3x^3−42x
Compute the difference quotient
[f(x+h)−f(x)]/h,h≠0
I checked my work like 3 times and still got [(-2x^3)+(3hx^2)+(3xh^2)+(h^3)-(42h)]/h
Is it wrong?
Answers
Answered by
Steve
looks like you forgot that pesky 3 out front.
f(x+h) = 3(x+h)^3 - 42(x+h)
= 3x^3 + 9x^2h + 9xh^2 + 3h^3 - 42x - 42h
f(x) = 3x^3 - 42x
subtract to get
9x^2h + 9xh^2 + 3h^3 - 42h
now divide by h to get
9x^2 + 9xh + 3h^2 - 42
f(x+h) = 3(x+h)^3 - 42(x+h)
= 3x^3 + 9x^2h + 9xh^2 + 3h^3 - 42x - 42h
f(x) = 3x^3 - 42x
subtract to get
9x^2h + 9xh^2 + 3h^3 - 42h
now divide by h to get
9x^2 + 9xh + 3h^2 - 42
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