PbCl2 ==> Pb^+2 + 2Cl^-
Ksp = (Pb^+2)(Cl^-)
You have the solubility of PbCl2. Pb^+2 will be the same; Cl^- will be twice that. Substitute those two numbers into the Ksp expression and solve for Ksp.
The solubility of lead (II) chloride (PbCl2) is 1.6 x 10^-2 M. What is the Ksp of PbCl2?
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