Asked by anonymous
the solubility of MG(OH)2 is 0.61 g/L
What must be the PH of this solution.
and thx dr. bob for last question
What must be the PH of this solution.
and thx dr. bob for last question
Answers
Answered by
DrBob222
You must mean Mg(OH)2.
Mg(OH)2 ==> Mg^+2 + 2OH^-
If solubility of Mg(OH)2 is 0.61 g/L, convert that to moles/L. moles = grams/molar mass. Call the solubility in moles/L = S
That is Mg(OH)2. Thus (Mg^+2) = S and (OH^-) = 2S. Use that to calculate pOH and pH from that.
Mg(OH)2 ==> Mg^+2 + 2OH^-
If solubility of Mg(OH)2 is 0.61 g/L, convert that to moles/L. moles = grams/molar mass. Call the solubility in moles/L = S
That is Mg(OH)2. Thus (Mg^+2) = S and (OH^-) = 2S. Use that to calculate pOH and pH from that.
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