Asked by Anonymous
If the molar solubility of lead iodide is 2.4 x 10^-3M. Calculate the Ksp.
Answers
Answered by
DrBob222
PbI2 ==> Pb^+2 + 2I^-
Ksp = (Pb^+2)(I^-)^2
Therefore, (Pb^+2) = 2.4 x 10^-3M
and (I^-) = 4.8 x 10^-3 M.
Plug into Ksp expression and solve for Ksp.
Ksp = (Pb^+2)(I^-)^2
Therefore, (Pb^+2) = 2.4 x 10^-3M
and (I^-) = 4.8 x 10^-3 M.
Plug into Ksp expression and solve for Ksp.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.