Question

assuming the following reaction proceeds in the forward direction, what is oxidized and what is reduced?

Cu2+ (aq) + Ca(s) --> Cu (s) + Ca2+ (aq)
Oxidation is the loss of electrons.
Reduction is the gain of electrons.
Cu goes from +2 on the left to 0 on the right.
Ca goes from 0 on the left to +2 on the right.

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