Asked by Anonymous

Assuming this reaction occurred, how many moles of NH3 would be made if 6 mol H2 were actually used?
3(H2) + (N2) --> 2(NH3)
Answered by oobleck
6 = 3*2, so you would get 2*2 moles of NH3
Answered by DrBob222
To show the units cancel and where that 2*2 comes from we have
6 mols H2 x (2 mol NH3/3 mols H2) = 6*2/3 = 2*2 = 4 mols NH3 produced.
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