Asked by bob
a 60 kilogram student sitting on a hardwood floor accelerates at 1.3 meters per second squared when pulled by a 240 newton horizontal force. what is the coefficient of friction between the student and the floor?
Answers
Answered by
drwls
The net accelerating force is F = M a = 78 N. That means the friction force is
Ff = 240 - 78 = 162 N
The coefficient of friction is
(162 N)/(M*g) = ___
Ff = 240 - 78 = 162 N
The coefficient of friction is
(162 N)/(M*g) = ___
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