Asked by Nadia

17. A 60.-kilogram student climbs a ladder a vertical distance of 4.0 meters in 8.0 seconds. Approximately how much total work is done against gravity by the student during the climb?


 
Answered by Henry
Fs = mg = 60 kg * 9.8 N./kg = 588 N. =
Weight or force of student.

W = F*d = 588 * 4 = 2352 Joules.

Answered by Alex
566
Answered by Anonymous
2.4
Answered by Anonymous
jkjk
Answered by ocie
FS = MG = 60Kg X 9.8 N/Kg x 4
= 588 x 4= 2352 or 2400 Joules
Answered by Negus
LMAO HE ASKED THE QUESTION IN 2012