Asked by Nadia
                17. A 60.-kilogram student climbs a ladder a vertical distance of 4.0 meters in 8.0 seconds. Approximately how much total work is done against gravity by the student during the climb?
	
 	
            
            
        Answers
                    Answered by
            Henry
            
    Fs = mg = 60 kg * 9.8 N./kg = 588 N. = 
Weight or force of student.
W = F*d = 588 * 4 = 2352 Joules.
 
    
Weight or force of student.
W = F*d = 588 * 4 = 2352 Joules.
                    Answered by
            Alex
            
    566
    
                    Answered by
            Anonymous
            
    2.4
    
                    Answered by
            Anonymous
            
    jkjk
    
                    Answered by
            ocie
            
    FS = MG = 60Kg X 9.8 N/Kg x 4
= 588 x 4= 2352 or 2400 Joules
    
= 588 x 4= 2352 or 2400 Joules
                    Answered by
            Negus
            
    LMAO HE ASKED THE QUESTION IN 2012
    
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