Asked by cel
A 9.0 x 10^-3 kg ball is attached to a 3.6 x 10^-2 mass (M) by string that passes through a hole in a horizontal frictionless surface. The ball travels in a circular path of radius 0.35 m. What is the speed of the ball?
I know the answer is 3.7 m/s, but I'm not sure how to get to the answer :S
I know the answer is 3.7 m/s, but I'm not sure how to get to the answer :S
Answers
Answered by
bobpursley
well,you know the tension in the string has to equal the weight in the center, and equal centripetal force.
3.6E-2* g= 9E-3*v^2/.35
solve for v.
3.6E-2* g= 9E-3*v^2/.35
solve for v.
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