Asked by Anonymous
A ball of mass 0.1 kg is attached to a rubber band, which we can model as a spring of stiffness 8 N/m. With one end of the rubber band fixed, you throw the ball vertically upward with an initial speed of 14 m/s. At the moment the ball leaves your hand, the rubber band is already stretched 0.1 m from its unstretched position. What is the maximum height the ball will rise (relative to where it was thrown)?
Answers
Answered by
bobpursley
initial KE+initialPEspring=finalKE+finalPEspring+finalgpe
1/2 m 14^2+1/2 k .1^2=0+1/2 k h^2+mgh
solve for h.
1/2 m 14^2+1/2 k .1^2=0+1/2 k h^2+mgh
solve for h.
Answered by
Anonymous
A 0.4 RUBBER BALL FALLS TO THE GROUND AT 8.0 M/S. IF IT BOUNCES BACK UPWARDS AT THE SAME SPEED,WHAT IS THE IMPULSE ACTING ON THE BALL?
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