Asked by Claire
A string of length 50cm is used to hang a picture frame from a nail hammered on a smooth wall. The frame is 20 cm wide and weighs 10N. It hangs symetrically.
The angle which each part of the string makes with the vertical is 23.6.
- State the magnitude and direction of the force on the nail.
- Calculate the tension in the string.
I tried to work the first part and couldn't do it. Then I triedd the second part. Can anyone check my working and tell me whther it's right please?
Resolve vertically:
T1 Sin 66.4 +T2 Sin 66.4 = 10N
Resolve horizontally:
T1Cos 66.4 = T2 Cos66.4
The I solved them simultaneously.
T1 = 5N and T2=5N. Therefore tension in string is 10N.
The angle which each part of the string makes with the vertical is 23.6.
- State the magnitude and direction of the force on the nail.
- Calculate the tension in the string.
I tried to work the first part and couldn't do it. Then I triedd the second part. Can anyone check my working and tell me whther it's right please?
Resolve vertically:
T1 Sin 66.4 +T2 Sin 66.4 = 10N
Resolve horizontally:
T1Cos 66.4 = T2 Cos66.4
The I solved them simultaneously.
T1 = 5N and T2=5N. Therefore tension in string is 10N.
Answers
Answered by
bobpursley
I don't have a clue what you did, but it was wrong. Your static equations are correct.
T1+T2=10/sin66.2
T1-T2=0 Or T1=T2 then
2T1=10/sin66.2
which does not lead you to your answers.
T1+T2=10/sin66.2
T1-T2=0 Or T1=T2 then
2T1=10/sin66.2
which does not lead you to your answers.
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