A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what distance from the left end of the rod should a 0.6kg mass be hung to balance the rod?

Answer 1

the center of mass of the rod is at 25 cm

15 * 0.2 = x * 0.6

distance from left end is ... 40 + x

Answer 2

X=0.05 m
40+5=45 cm
What formula did you use