A yo-yo has a string length of 0.200 m

Question

What is the slowest speed at which you can spin it to keep it in a fixed path?

What is this, and how do you find it?
Thanks

Answer 1

define "fixed path"

Answer 2

The question just says "the slowest speed at which you can spin it to keep it in a fixed path"

Answer 3

Ok, then I can't help, a fixed path is a straight line. I can't imagine that with a yo-yo. So if it is in a circle, is it horizontal circle or vertical. Normally a yoyo would be operating in a vertical orbit, but that hardly is a fixed path. I will see if I can get you some other eyes on this.

Answer 4

Im sorry, I forgot...

Its a vertical circle.

Answer 5

If it is a vertical path then and it is sleeping at the end of the string, it is like a rock at the end of a string and the centripetal acceleration at the top of the loop must be equal or greater than 1 g or the string will go slack and the rock fall out of the vertical circle.
v^2/r >/= g for circular path
so v at least sqrt ( g r )
v = sqrt (9.8 * .2) = sqrt (1.96)
v = 1.4 m/s