Asked by Megan
A yo-yo has a string length of 0.200 m
What is the slowest speed at which you can spin it to keep it in a fixed path?
What is this, and how do you find it?
Thanks
What is the slowest speed at which you can spin it to keep it in a fixed path?
What is this, and how do you find it?
Thanks
Answers
Answered by
bobpursley
define "fixed path"
Answered by
Megan
The question just says "the slowest speed at which you can spin it to keep it in a fixed path"
Answered by
bobpursley
Ok, then I can't help, a fixed path is a straight line. I can't imagine that with a yo-yo. So if it is in a circle, is it horizontal circle or vertical. Normally a yoyo would be operating in a vertical orbit, but that hardly is a fixed path. I will see if I can get you some other eyes on this.
Answered by
Megan
Im sorry, I forgot...
Its a vertical circle.
Its a vertical circle.
Answered by
Damon
If it is a vertical path then and it is sleeping at the end of the string, it is like a rock at the end of a string and the centripetal acceleration at the top of the loop must be equal or greater than 1 g or the string will go slack and the rock fall out of the vertical circle.
v^2/r >/= g for circular path
so v at least sqrt ( g r )
v = sqrt (9.8 * .2) = sqrt (1.96)
v = 1.4 m/s
v^2/r >/= g for circular path
so v at least sqrt ( g r )
v = sqrt (9.8 * .2) = sqrt (1.96)
v = 1.4 m/s
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