Question

Any help would be great, even if it is just a way to start or a formula.

Calculate the heat necessary to convert 10.0 g of water (just melted) at 0 degrees Celcius to water at 20 degrees Celcius, assuming that the specific heat remains constant at 1 cal/gram degrees celcius.

Answer 1

i used the formula m(delta T)Cp=delta H

(10.0)(20.0-0.00)= x

and so x = 200... is that correct, if so would the units be degrees celcius?

Answer 2

(10.0 g water) (delta 20 degrees C)(4.184J/g x C) = 836.8 J needed to heat the water.

You just forgot to multiply the specific heat.