Question

How much heat is released when a mixture containing 10.0g CS2 and 10.0 g Cl2 reacts by the equation.

CS2 + 3Cl2 ----> S2Cl2 + CCl4
Delta H = -230 kJ

Answer 1

Determine which is the limiting reagent using simple stoichiometry.
I assume that is -230 kJ/MOLE CS2.
Then use proportions to determine delta H.

Answer 2

what do you mean by proportions???

Answer 3

After you find the limiting reagent, (let's assume it is Cl2 but you will need to do the arithmetic to determine if it is), use that number to determine the mols CS2 that reacts, then a proportion is as follows:
(1 mol CS2/-230 kJ) = (??mols CS2/xx kJ.
The ??mols CS2 is from your first calculation, and that leaves only the 1 unknown (xx kJ).
Of course you may use dimensional analysis for the same thing.
-230 kJ * (xx mols CS2/1 mol CS2) = ??