Question
How much heat is released if 2.00 moles
CF2Cl2 reacts with 70.0 g F2 with a 75.0
percent yield?
CF2Cl2 + F2 ! CF4 + Cl2
H for this reaction is -401 kJ/mol rxn.
1. 553 kJ
2. 739 kJ
3. 985 kJ
4. 601 kJ
5. 1069 kJ
6. 802 kJ
CF2Cl2 reacts with 70.0 g F2 with a 75.0
percent yield?
CF2Cl2 + F2 ! CF4 + Cl2
H for this reaction is -401 kJ/mol rxn.
1. 553 kJ
2. 739 kJ
3. 985 kJ
4. 601 kJ
5. 1069 kJ
6. 802 kJ
Answers
First determine which is the limiting reagent. Use that to determine how much of the CF2Cl2 is used for 100% yield. Then 401 kJ/mol x mols CF2Cl2 use = kJ produced for 100% yield.
kJ produced x 0.75 = heat produced with 75% yield. This assumes that other reactions producing heat do not occur.
kJ produced x 0.75 = heat produced with 75% yield. This assumes that other reactions producing heat do not occur.
Answer 1; 553 kJ
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