Asked by Leah
How much heat would be released by the complete combustion of 35.0 g of propane, C3H8?
(The molar mass of propane is 44.09 g/mol.)
C3H8 + 5O2 --> 3CO2 + 4H2O LaTeX: \Delta Δ H = -2044 kJ
(The molar mass of propane is 44.09 g/mol.)
C3H8 + 5O2 --> 3CO2 + 4H2O LaTeX: \Delta Δ H = -2044 kJ
Answers
Answered by
DrBob222
2044 kJ x (35.0/44.09) = ? g
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