Question

given one point on the graph
(-2/3,(2,5) and the slope, m=-3, develop an equation in te slope intercept format

Answer 1

(-2/3 , 5/2), m = - 3.

y = mx + b = 5/2,
mx + b = 5/2,
-3(-2/3) + b = 5/2,
2 + b = 5/2,
b = 5/2 - 2,
2 = 4/2,
b = 5/2 - 4/2,
b = 1/2.

Eq: y = -3x + 1/2.