Asked by Anonymous
How do you find the implicit differentiation of 2/x + 2/y = 5?
Answers
Answered by
Damon
(-2/x^2) dx/dx - (2/y^2)dy/dx = 0
-(1/x^2) dx = (1/y^2) dy
dy/dx = -y^2/x^2
but y = 2x/(5x-2)
y^2 = 4x^2/(5x-2)^2
so
dy/dx = -4/(5x-2)^2
-(1/x^2) dx = (1/y^2) dy
dy/dx = -y^2/x^2
but y = 2x/(5x-2)
y^2 = 4x^2/(5x-2)^2
so
dy/dx = -4/(5x-2)^2
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