Bonds broken: 6 Cl-F and 2 O=O.
Bonds formed: 2 Cl-O and 6 O-F
delta H = (sum reactants)-(sum products) = delta H rxn.
It is unclear is this is the reaction you want.
Use the bond energies given in the "Bond Energy" table (can be gained from google) to estimate the delta Ho for the reaction given below.
2ClF3(g) + 2O2(g) Cl2O(g) + 3OF2(g)
I did this:
1530 + 996 - (410 + 570) = 1546.
But the answer was wrong. I don't know where I did wrong.
Thanks!
1 answer