Asked by Robin
for bond energies if tehy give u a diagram of the structure for whatever like c--h--o==h or soemthing amd a chart with c--h=-670 Kj /mol or whatever do u just add all of the KJ/mol together? but what if they only want kJ? would you just multply whatever kJ/mol *1 mol??
how do i go from kJ/mol>>>kJ
how do i go from kJ/mol>>>kJ
Answers
Answered by
DrBob222
delta Ho rxn = sumBE reactants - sum BE products.
You add them togther for reactants and add them together for the products, then subtract as above.
That give you delta H rxn/mol. If you want some other value, say half a mole, divide by 2.
You add them togther for reactants and add them together for the products, then subtract as above.
That give you delta H rxn/mol. If you want some other value, say half a mole, divide by 2.
Answered by
Robin
ummm so is delta H kJ/mol?
i want just kJ. do i just mult kJ/mol *1mol?
i want just kJ. do i just mult kJ/mol *1mol?
Answered by
DrBob222
Yes, you calculate kJ/mol when you do this. If you want kJ per half mole, then multiply by 1/2 and that gives you kJ for whatever problem you are solving. However, it will ALWAYS be kJ/something; i.e., kJ/mol, kJ/g, kJ/500 mg or what have you. If you want to type in your problem it might help explain.
Answered by
Robin
...use the enervy values to estimate delta H for each of the reactions
_______kJ
_______kJ
Answered by
DrBob222
per mol is understood. So calculate delta H in kJ/mol and just omit the per part.
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