Ask a New Question

Question

At equilibrium, [S(CH2CH2Cl)2] = 350 M, [SCl2]=.325M, and [C2H4] =.273 M for the reaction below. SCl2 + 2C2H4 = S(CH2CH2Cl)2
What is the Kc?
14 years ago

Answers

DrBob222
SCl2 + 2C2H4 = S(CH2CH2Cl)2'

Kc = [S(CH2CH2Cl)2]/(C2H4)^2(SCl2)
Substitute the numbers and solve for Kc.

14 years ago

Related Questions

At 25.0o C, the equilibrium 2 NOBr(g) ¡ê 2 NO(g) + Br2(g) is rapidly established. When 1.10 g of NOB... 1. In an equilibrium, A + B ---> C + D; "A" & "B" are mixed in a vessel at temperature "T". The ini... What happens to the equilibrium constant when a catalyst is added to the reaction mixture. A. In... How has the equilibrium been modified in Haber Process? what is the heat value for the following... Consider this equilibrium N2(g) + H2(g) <==> NH3(g) +94 kJ The equilibrium law exoression for the... In the equilibrium lab, you place the fulcrum (pivot point) at the 25 cm mark on the meter stick. T... The equilibrium between three substances, a, B and c is shown below. A(g) + B(g) C(g) Initially... For the equilibrium br2(g)⇌2Br(g), Kc=0.00104 at 1285 degrees C. What will be the equilibrium concen... At 2,000 K, the equilibrium constant for the reaction below is Kc = 3.92. Br2(g) ⇌ 2 Br(g) Wha...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use