Asked by Raj
The equilibrium between three substances, a, B and c is shown below.
A(g) + B(g) C(g)
Initially there were 0.1 mol of a and 0.2 mol of B in the reaction mixture. a and B reacted together to produce an
equilibrium mixture containing 0.04 mol of c. The total volume of the mixture was 2.00 dm3.
a Calculate the number of moles of a and B at equilibrium.
b Calculate the concentrations of a, B and c at equilibrium.
c i Write the equilibrium expression for Kc
.
ii Calculate the value of Kc
and give the units.
A(g) + B(g) C(g)
Initially there were 0.1 mol of a and 0.2 mol of B in the reaction mixture. a and B reacted together to produce an
equilibrium mixture containing 0.04 mol of c. The total volume of the mixture was 2.00 dm3.
a Calculate the number of moles of a and B at equilibrium.
b Calculate the concentrations of a, B and c at equilibrium.
c i Write the equilibrium expression for Kc
.
ii Calculate the value of Kc
and give the units.
Answers
Answered by
DrBob222
a. Do this the same way as the previous problem for moles.
b. mols/volume in dm^3 = concentration.
c. Kc = (C)/(A)(B)
ii. Plug in the concentration values from part b and calculate Kc.
Post your work if you get stuck.
b. mols/volume in dm^3 = concentration.
c. Kc = (C)/(A)(B)
ii. Plug in the concentration values from part b and calculate Kc.
Post your work if you get stuck.
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