Asked by Q
Consider this equilibrium
N2(g) + H2(g) <==> NH3(g) +94 kJ
The equilibrium law exoression for the balanced chemical equationwould be
A. [N2][H2]/[NH3]
B. [NH3]/[H2][N2]
C. [NH3]2/[H2][N2]
D. [NH3]2/[H2]3[N2]
E. 2[NH3]2/3[H2]3[N2]
N2(g) + H2(g) <==> NH3(g) +94 kJ
The equilibrium law exoression for the balanced chemical equationwould be
A. [N2][H2]/[NH3]
B. [NH3]/[H2][N2]
C. [NH3]2/[H2][N2]
D. [NH3]2/[H2]3[N2]
E. 2[NH3]2/3[H2]3[N2]
Answers
Answered by
DrBob222
First, balance the equation.
Then Keq = (right side concns)/(left side concns), with each concn raised to a power indicated by the coefficient in the balanced equation..
Then Keq = (right side concns)/(left side concns), with each concn raised to a power indicated by the coefficient in the balanced equation..
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