Asked by Esora
A soccer ball is kicked into the air at an angle of 38 degrees above the horizontal. The initial velocity of the ball is +30.0m/s. How long is the ball in the air?
-What is the maximum height reached by the ball?
-What is the horizontal distance traveled by the ball?
-What is the maximum height reached by the ball?
-What is the horizontal distance traveled by the ball?
Answers
Answered by
Damon
Vi = 30 sin 38
h = Ho + Vi t - 4.9 t^2
h = 0 at ground
so
0 = 0 + Vi t - 4.9 t^2
t (Vi-4.9 t) = 0
t = 0 (it started at ground
t = Vi/4.9 when it hit ground again
max h is when v = 0
v = Vi -9.8 t
0 = Vi -9.8 t
t = Vi/9.8 at top *** this should be half the whole time in the air***
h = 0 +Vi t - 4.9 t^2
using that t which should be half the total t
u = 30 cos 38
d = u t where t is the total time in the air (not the half time you used for part B)
h = Ho + Vi t - 4.9 t^2
h = 0 at ground
so
0 = 0 + Vi t - 4.9 t^2
t (Vi-4.9 t) = 0
t = 0 (it started at ground
t = Vi/4.9 when it hit ground again
max h is when v = 0
v = Vi -9.8 t
0 = Vi -9.8 t
t = Vi/9.8 at top *** this should be half the whole time in the air***
h = 0 +Vi t - 4.9 t^2
using that t which should be half the total t
u = 30 cos 38
d = u t where t is the total time in the air (not the half time you used for part B)
Answered by
swag
3.766 seconds, 25.544 m, 88.886 m,
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.