area= s^2+hs
Volume=s^2*h or 108/s^2=h
area= s^2+108/s
dA/ds= 2s-108/s^2=0
2s^3=108
solve.
A cardboard box of 108in cubed volume with a square base and no top constructed. Find the minimum area of the cardboard needed. (Optimization)
4 answers
Would the answer be 3.7?
you are looking for area, finding s is only the first step. Look at the area formula.
answer in the back of the book is 180in squared
but im not getting that answer
but im not getting that answer