Asked by Anonymous
A cardboard box of 108in cubed volume with a square base and no top constructed. Find the minimum area of the cardboard needed. (Optimization)
Answers
Answered by
bobpursley
area= s^2+hs
Volume=s^2*h or 108/s^2=h
area= s^2+108/s
dA/ds= 2s-108/s^2=0
2s^3=108
solve.
Volume=s^2*h or 108/s^2=h
area= s^2+108/s
dA/ds= 2s-108/s^2=0
2s^3=108
solve.
Answered by
Anonymous
Would the answer be 3.7?
Answered by
bobpursley
you are looking for area, finding s is only the first step. Look at the area formula.
Answered by
Anonymous
answer in the back of the book is 180in squared
but im not getting that answer
but im not getting that answer
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