Asked by jake
a cardboard box which has a volume of 60 cubic inches and has the dimensions of (x-1) (x-6) (x-2) what is the lenght, width and height of the box
Answers
Answered by
bobpursley
60=(x-1)(x-6)(x-2)
60=(x^2-7x+6)(x-2)
60=(x^3-2x^2-7x^2+14x+6x-12)
x^3-9x^2+20x-72=0
Hmmmm. Ok, graph this equation, find where it crosses the x axis, I see x=7.59
which makes lwh then 6.59;1.59;5.59
check 6.59*1.59*5.59=
60=(x^2-7x+6)(x-2)
60=(x^3-2x^2-7x^2+14x+6x-12)
x^3-9x^2+20x-72=0
Hmmmm. Ok, graph this equation, find where it crosses the x axis, I see x=7.59
which makes lwh then 6.59;1.59;5.59
check 6.59*1.59*5.59=
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