Asked by kim
from a cardboard box 12 in by 8 inches are cut out so the sides can be folded up to make a box . What dimentions will yield a maximum volume? What is maximum volume?
we got our V = 4x^3--40x^2+96x
V'=12x^2-80x +96
then we know to use quadratic equation
I get 20( +/-) sqrt 112/6
this is where stuck please help thanks
we got our V = 4x^3--40x^2+96x
V'=12x^2-80x +96
then we know to use quadratic equation
I get 20( +/-) sqrt 112/6
this is where stuck please help thanks
Answers
Answered by
Steve
you have two answers. One will be greater than 8, so it is useless. So, use
(10-2√7)/3 = 1.57
max v = 64(10+7√7)/27
(10-2√7)/3 = 1.57
max v = 64(10+7√7)/27
Answered by
Scott
the quadratic solutions are relative max/min points on the graph (you obviously want the max)
test the solutions in the original equation
x < 4 because of the 8 in side
test the solutions in the original equation
x < 4 because of the 8 in side
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