When 2.53 g of NaOH(s)(40.0g/mol) dissolves in 100.0 g of water, the temperature of the solution changes from 20 degrees C to 26.3 degrees C. Calculate qrx in KJ/mol specific heat of the solution is 4.18 J/(g*K)

Answer 1

q = mass water x specific heat water x (Tfinal-Tinitial) = ?? Joules and change to kJ.
Then kJ/# moles = kJ/mol.
You can find moles by 2.53/molar mass NaOH.

Answer 2

Thank you for all of your help DrBob!!!!