Asked by Anonymous
30.0 mL of 1.50 M NaOH is diluted to 50.0 mL. What is the resulting pH?
Answers
Answered by
DrBob222
mL x M = mL x M
Solve for M NaOH.
That equals (OH^-).
pOH = -log(OH^-)
Then pH + pOH = pKw = 14
Solve for pH.
Solve for M NaOH.
That equals (OH^-).
pOH = -log(OH^-)
Then pH + pOH = pKw = 14
Solve for pH.
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