Question

36 g of HCl and 40 g of NaOH combine to form 58 g of NaCl. What is the amount of water produced in this process?

Answer 1

H Cl + NaOH --> NaCl + H2O
H Cl = 1 + 35 = 36.5 grams / mol so we have 1 mol
NaOH = 23 + 16 + 1 = 40 grams / mol so we have one mol
NaCl = 23 + 35 = 58 grams / mol so we have 1 mol
H2O = 2+16 = 18 grams/mol
so we get one mol of water, 18 grams

Answer 2

Another way to do this is to use the Law of conservation of matter. Matter is neither created nor destroyed
HCl + NaOH --> NaCl + H2O
36.......40...........58..........x
started with 76 g. Must end up with 76 g. 58 from NaCl; therefore, 76-58 = 18 g for H2O
36 + 40 = 58 + X
X = 36 + 40 - 58
X = 18 g.H2O

Answer 3

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