Asked by Justin
Using L'Hopital's Rule, find the limit:
lim x->0+ (as x approaches 0 from the right) of sinx/x^(1/3)
lim x->0+ (as x approaches 0 from the right) of sinx/x^(1/3)
Answers
Answered by
Reiny
limit (sinx/x^1/3)) as x --> 0
= lim (cosx/((1/3)x^(-2/3))
= lim ((cosx)(3x^(2/3))
= (cos0)(0) = 0
= lim (cosx/((1/3)x^(-2/3))
= lim ((cosx)(3x^(2/3))
= (cos0)(0) = 0
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