Question
Using L'Hopital's rule find the limit if exists of;
lim x->1 (cosx)/(pi-2x)
I got (sinx)/2
but i am not sure about this> Can anyone help me out
lim x->1 (cosx)/(pi-2x)
I got (sinx)/2
but i am not sure about this> Can anyone help me out
Answers
Reiny
Most students forget the usual first step in any Limit question, and that is to substitute the approach value into the expression.
If you get 0/0 then you have a limit question that needs some work
If you get a real number, that is your answer and you are done
so lim (cosx)/(pi - 2x) as x ---> 1
= cos 1/(pi - 2)
= .473288
If you get 0/0 then you have a limit question that needs some work
If you get a real number, that is your answer and you are done
so lim (cosx)/(pi - 2x) as x ---> 1
= cos 1/(pi - 2)
= .473288