Question

Using L'Hopital's rule find the limit if exists of;

lim x->1 (cosx)/(pi-2x)


I got (sinx)/2
but i am not sure about this> Can anyone help me out

Answers

Reiny
Most students forget the usual first step in any Limit question, and that is to substitute the approach value into the expression.
If you get 0/0 then you have a limit question that needs some work
If you get a real number, that is your answer and you are done

so lim (cosx)/(pi - 2x) as x ---> 1
= cos 1/(pi - 2)
= .473288

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