Ask a New Question

Question

use l'hopital rule on sin(x)/x. x=0
5 years ago

Answers

bobpursley
well, the function is indeterminate: 0/0
first derivative: cos(x)/1=1
limit is 1 as x approaches zero.
5 years ago

Related Questions

Using L'Hopital's rule find the limit if exists of; lim x->1 (cosx)/(pi-2x) I got (sinx)/2... Using L'Hopital's Rule, find the limit: lim x->0+ (as x approaches 0 from the right) of sinx/x^(1... Using l'hopital's rule, find the limit as x approaches infinity of (e^(6/x)-6x)^(X/2) I know l'hop... Using l'hopital's rule, find the limit as x approaches zero of (e^(6/x)-6x)^(X/2) I know l'hopital... Using L'Hôpital's rule, evaluate lim of xe^(-x) as x approaches infinity Use L’Hopital’s rule to find the limit of this sequence (n^100)/(e^n) ...If you do L'Hop. Rule... Use l'hopital's Rule to evaluate lim x in 0 of (4x(cos 6x-1 )) / sin 3x-3x use L'Hopital's Rule to evaluate lim (4x(cos 8x-1))/(sin 8x - 8x) as x->0 L'hopital's question below: lim x -> 0 from the positive direction of ( 5^(sin(x)) - 1 )/ (x) Evaluate using L'Hopital Rule? lim as x approaches x from left (1-x)^(3/x)
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use