Question

Given Triange ABC with
an area of 100.2 a = 32.5 c = 29.2
Find angle B, expressed in degrees.

Answer 1

Area = (1/2)ac*sinB = 100.2,
(1/2)*32.5*29.2sinB = 100.2,
474.5sinB = 100.2,
sinB = 0.2112,
B = 12.2 Deg.