Asked by Diandra

In a sample of 171, the mean is 58 with a population standard deviation of 4.8. Can someone help me figure out what is the 90% confidence interval of the true mean? Thank you.

Answers

Answered by PsyDAG
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the Z score for .4500 from mean (Z = 1.645)

90% conf. Interval = mean ± 1.645(SEm)

SEm (Standard Error of the mean) = SD/?(n-1)

There is a difference if you want to find confidence intervals for distribution of scores or distribution of means.
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