Asked by jack
A 4.70 g sample of a certain gas occupies 530. mL at STP. What mass of the same gas is present in a 1.15 L container at 40.5°C and 785 mm Hg?
Answers
Answered by
DrBob222
A confusing problem.
Use PV = nRT and solve for n of the 4.70 g gas at STP, the convert n to molar mass. That is n = grams/molar msss. You know n and grams, solve for molar mass.
Then use PV = nRT again at the new conditions and solve for n in the new container at the new conditions. Then use n = grams/molar mass. You know molar mass and n, solve for grams.
Use PV = nRT and solve for n of the 4.70 g gas at STP, the convert n to molar mass. That is n = grams/molar msss. You know n and grams, solve for molar mass.
Then use PV = nRT again at the new conditions and solve for n in the new container at the new conditions. Then use n = grams/molar mass. You know molar mass and n, solve for grams.
Answered by
Ncam Vusoh
5 mol/dm^3
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