Asked by julia
23. A 32.3 L sample of a gas at 305oC and 1.20 atm is to be cooled at constant pressure until its volume becomes 28.4L. What will be the new gas temperature?
Tf = Vf*Ti/Vi
Tf =28.4L x (305+273)K / 32.3L
= (28.4)(578)K / 32.3
= 16415.2/32.3
Tf = 508K
I got this one wrong on a test please let me know what I'm doing wrong???
Tf = Vf*Ti/Vi
Tf =28.4L x (305+273)K / 32.3L
= (28.4)(578)K / 32.3
= 16415.2/32.3
Tf = 508K
I got this one wrong on a test please let me know what I'm doing wrong???
Answers
Answered by
DrBob222
I get 508.2 K which rounds to 508 K. I don't see anything wrong with what you've done. Perhaps the answer was supposed to be in celsius.
There are no AI answers yet. The ability to request AI answers is coming soon!