Asked by Katie

An unknown material absorbs 1,930 J of heat when it changes from 25 °C to 35°C. The sample weighs 500g. What is the specific heat of this material?
Answered by Katie
Would you use q/mass*change in T= c
so 1930J/(500g*10degC)=.386J/degC?
Answered by DrBob222
Yes. That looks right to me.
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