Asked by sami
find the x and y intercepts:
3x - 2y = -12
i know for the x intercept, put y=0 in the equation,s olve for x. For the y intercept, do the reverse. But i still don't understand how to solve it. Its just majorly fustrating me. And i can't go to school and ask a teacher because im suspended for 30 days and im not allowed on any CCPS property.
3x - 2y = -12
i know for the x intercept, put y=0 in the equation,s olve for x. For the y intercept, do the reverse. But i still don't understand how to solve it. Its just majorly fustrating me. And i can't go to school and ask a teacher because im suspended for 30 days and im not allowed on any CCPS property.
Answers
Answered by
MathMate
The y-intercept is where the line cuts the y-axis, therefore you put x=0 and solve for the value of y.
y=-12/-2=6 in this case.
The x-intercept is where the line cuts the x-axis, therefore, put y=0, and solve for x.
x=-12/3 = -4
If you need more explanations, post.
y=-12/-2=6 in this case.
The x-intercept is where the line cuts the x-axis, therefore, put y=0, and solve for x.
x=-12/3 = -4
If you need more explanations, post.
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