Asked by ddd
find x an y intercepts
f(x)=7x^2+6x-7
f(x)=(x-7)^2-4
f(x)=7x^2+6x-7
f(x)=(x-7)^2-4
Answers
Answered by
Steve
y-intercepts are easy. Just plug in x=0 and evaluate y
x-intercepts involve factoring the quadratic and pick each x-value where y=0.
1st:
y-intercept is at (0,-7)
f(x) = 7x^2 + 6x - 7
use quadratic formula to find y = 0 when x = (-3 ± √58)/7
2nd:
y-intercept is at (0,-4)
for x-intercepts, you want
x-7 = ±2
so, x = 5 or 9
x-intercepts involve factoring the quadratic and pick each x-value where y=0.
1st:
y-intercept is at (0,-7)
f(x) = 7x^2 + 6x - 7
use quadratic formula to find y = 0 when x = (-3 ± √58)/7
2nd:
y-intercept is at (0,-4)
for x-intercepts, you want
x-7 = ±2
so, x = 5 or 9
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