The x intercepts are where y = 0. There are two of them.
Note that y = x^2 -6x -7 = (x-7)(x+1),
by factoring.
y is zero when either of those factors is zero.
The y intercept is where x = 0. The equation tells you that happens at y = -7.
How do I find the x intercepts of the parabola y=x^2-6x-7?
Thanks
2 answers
The X-intercepts are the points where the parabola crosses the X-axis when
Y=0.The x-intercepts are also the
solutions to the equation:
Y=X^2-6X-7=0,solve for X by factoring,
(X+1)(X-7)=0, X+1=0,X=-1; X-7=0,X=7.
The X-INT(solutions)are:X=-1, X=7.
Y=0.The x-intercepts are also the
solutions to the equation:
Y=X^2-6X-7=0,solve for X by factoring,
(X+1)(X-7)=0, X+1=0,X=-1; X-7=0,X=7.
The X-INT(solutions)are:X=-1, X=7.
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