Question
Problem#8: Metabolism of alcohol (ethanol, C2H5OH) by the body takes place according to the reaction:
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l)
ΔHo = -1367 kJ
Determine the number of “food calories” (Cal) supplied by the alcohol in a 12-oz (355-mL) bottle of “Molson Ice” beer that contains 4.50% alcohol by mass. Assume the density of the beer to be 1.00 g/mL. (1 Cal = 4.18 kJ; MM of C2H5OH = 46.1 g/mol)
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l)
ΔHo = -1367 kJ
Determine the number of “food calories” (Cal) supplied by the alcohol in a 12-oz (355-mL) bottle of “Molson Ice” beer that contains 4.50% alcohol by mass. Assume the density of the beer to be 1.00 g/mL. (1 Cal = 4.18 kJ; MM of C2H5OH = 46.1 g/mol)
Answers
4.50% by mass means 4.50 g EtOH/100 g solution. The density is 1.00 g/mL; therefore, that becomes 4.50 g EtOH/100 mL. How much alcohol is contained in 355 mL of the beer?
4.50 g EtOH x 355 mL/100 mL = 15.975 grams EtOH.
You get 1367 kJ for each 46 g EtOH according to the equation; therefore, there are
1367 kJ x 15.975/46 g = 474.73 kJ
Convert 474.73 kJ to kcal and that will be the same as the Cal (food energy).
Check my work. Check my thinking.
4.50 g EtOH x 355 mL/100 mL = 15.975 grams EtOH.
You get 1367 kJ for each 46 g EtOH according to the equation; therefore, there are
1367 kJ x 15.975/46 g = 474.73 kJ
Convert 474.73 kJ to kcal and that will be the same as the Cal (food energy).
Check my work. Check my thinking.
Related Questions
The unbalanced equation for the combustion of ethanol is as follows:
C2H5OH(l) + O2(g) ¨ CO2(g)...
2. Given the following equation, C2H5OH(l) + 3 O2(g)---> 2 CO2(g) + 3 H2O(l)
How many liter of...
Ethanol, C2H5OH or C2H6O, is mixed with gasoline and sold as gasohol. Given the following thermo-che...
An alcohol, Ethanol (C2H5OH), is present in 1L of wine that is 12% alcohol by volume. The density of...