Asked by Jessica
The reaction for the metabolism of sucrose, C12H22O11, is the same as for its combustion in oxygen to yield CO2(g) and H2O(l). The standard heat of formation of sucrose is -2230 kJ mol-1. Based upon data in Table 6.2 and problem 6.75 the amount of energy (in kJ) released by metabolizing 4.17 oz (118 g) of sucrose is?
Answers
Answered by
bobpursley
figure the moles of sucrose first.
Next,
energy=molessugar*2230Kj/mol
Next,
energy=molessugar*2230Kj/mol
Answered by
Abby
moles would be 118g divided by 342.3?
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